Guys I am working on ym CWNA paper and have hit a little point that I
cannot get passed (although you will probably think this is pretty
simple).

It is the calculation for a circuit as below.

AP--connector (A) -----Cable----Connector (B)----cable----Connector
(C)---Antenna (D)

AP is 100mW and the paper is explaining the calculation as below.

AP         Point A       Ponit B       Point C      Point D
100mW        -3dB         -3dB          -3dB         +12dBi
=100mW       /2            /2            /2         (x2x2x2)
=100mW       /2            /2            /2           x16
=50mW                      /2            /2           x16
=25mW                                    /2           x16
=200mW                                              

It was my understanding that all dB units (including dBi) are relative
units and can be added and subtracted from other dB units - therefore
the overall dB should be +3db = doubling the power - hey presto the
right answer!

What I cant fathom is the calc shown above - why have they suggested a
multiple of x2x2x2 ?

Can someone please explain why......only a little point but bloody
annoying when your are learning this stuff for the first time!

Thanks

r**@northamber.com (Rob D) wrote:
Show quoteHide quoteYep, it is simple.  Of course you have to be confident enough to
know when you are looking at a typo!  They left off one "x2",
because 12 dB is one 2x for each 3 dB, so that is a total of *4*
x2's that should be in that string.

Looks like your understanding of it is perfect, and what you
lack is understanding that you do understand it! :-)

Thanks guys - still a little worried about this but I will face it down
come final week before exam.

- I will probably put another post up here later...lol!

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